z^2-2(3+2i)+2+8i=0

Solution for z^2-2(3+2i)+2+8i=0 equation:

Simplifying
z2 + -2(3 + 2i) + 2 + 8i = 0
z2 + (3 * -2 + 2i * -2) + 2 + 8i = 0
z2 + (-6 + -4i) + 2 + 8i = 0

Reorder the terms:
-6 + 2 + -4i + 8i + z2 = 0

Combine like terms: -6 + 2 = -4
-4 + -4i + 8i + z2 = 0

Combine like terms: -4i + 8i = 4i
-4 + 4i + z2 = 0

Solving
-4 + 4i + z2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4i + 4 + z2 = 0 + 4

Reorder the terms:
-4 + 4 + 4i + z2 = 0 + 4

Combine like terms: -4 + 4 = 0
0 + 4i + z2 = 0 + 4
4i + z2 = 0 + 4

Combine like terms: 0 + 4 = 4
4i + z2 = 4

Add '-1z2' to each side of the equation.
4i + z2 + -1z2 = 4 + -1z2

Combine like terms: z2 + -1z2 = 0
4i + 0 = 4 + -1z2
4i = 4 + -1z2

Divide each side by '4'.
i = 1 + -0.25z2

Simplifying
i = 1 + -0.25z2